- Edge is 1, what’s the hypervolume?
- General formula for the bulk?

The solution for 1 can be obtained numerically.

For 2, you have time until the end of this year (2017). (Unless the solution will be published sooner than that.)

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- Edge is 1, what’s the hypervolume?
- General formula for the bulk?

The solution for 1 can be obtained numerically.

For 2, you have time until the end of this year (2017). (Unless the solution will be published sooner than that.)

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It looks like WolframAlpha already knows the answer. Sorry folks, this game is most probably already over.

25/4*(2+SQRT(5))*a^4

See you in a week!

An interesting debate and solution, no matter that WolframAlpha is that smart:

http://lesswrong.com/lw/omc/open_thread_feb_13_feb_19_2017/dn00

What do you have printed on your business card, mathemagician?

I don’t have a business card. Thanks for a flattering question anyway.

Finally one for you:

“Each of a million people puts his or her hat into a very large box. Each hat has its owner’s name on it. The box is given a good shaking, and then each person, one after another, randomly draws a hat out of the box. What is the probability that at least one person gets their own hat back?”

via One Million Hats

> Each of a million people puts his or her hat into a very large box …

Say every hat has its own ribbon, which is removed and also mixed in that box. What is the probability …

Well, evidently smaller.

What if the number of hats is countably infinite. What are the odds then? For at least one matching pair? For the infinite number of matches?

Say, that we have all the real numbers from 0 to 1. And a random function from and onto this same interval. How probable it is, that no number is mapped onto itself?

Say, that this probability is p. Then make a square 1 by 1. Which is the same as continuum many of those intervals, each with a random function onto itself. What are probabilities now?

Perhaps one day, we shall ask this question.

Thomas a bo kak meeting?

lp.

Not until 2020.

Hehe…

Samo 2020 se ne bo singularnosti.

Thomas’ response to Double_J:You have been wrong before, but just as confident as you are now. What I think about that – I’ll make a post shortly.